y^'-y=-1

Lösung

y^{^{'}} - y = - 1

y = - e^{t + c_{1}} + 1

Schritte zur Lösung

y^{'} (t) - y = - 1

Solve separable ODE:

y = - e^{t + c_{1}} + 1

y = - e^{t + c_{1}} + 1

y^{^{'}} = \frac{x + 4}{y ^{2}}

y^{^{'}} = \frac{4 x y}{x ^{2} + 1}

x y^{2} y^{^{'}} = x + x^{3}, y (1) = 2

\frac{d y}{d x} = \frac{1 + x}{y}

y^{^{'}} = \frac{sin ( x )}{y}, y (\frac{π}{2}) = 1