y^'=(3sin(x))/(sin(y)),y(0)= pi/2

Lösung

y^{^{'}} = \frac{3 sin ( x )}{sin ( y )}, y (0) = \frac{π}{2}

y = arccos (3 cos (x) - 3) + 2 πn, y = - arccos (3 cos (x) - 3) + 2 πn

Schritte zur Lösung

y^{'} (x) = \frac{3 sin ( x )}{sin ( y )}

Solve separable ODE:

y = arccos (3 cos (x) - 3) + 2 πn, y = - arccos (3 cos (x) - 3) + 2 πn

y = arccos (3 cos (x) - 3) + 2 πn, y = - arccos (3 cos (x) - 3) + 2 πn

3 y^{3} d y - 6 x^{4} d x = 0

\frac{d y}{d x} = y (8 x^{2} + 4)

(x) d x + (y e^{y}) d y = 0

y^{^{'}} = y - 3

y^{^{'}} + \frac{y}{6} = 3, y (- 1) = 0