5ye^{x^2+y}y^'=2x

Lösung

5 y e^{x^{2} + y} y^{^{'}} = 2 x

y = W (\frac{- e ^{- x^{2}} + c _{1}}{5 e}) + 1

Schritte zur Lösung

5 y e^{x^{2} + y} y^{'} (x) = 2 x

Solve separable ODE:

y = W (\frac{- e ^{- x^{2}} + c _{1}}{5 e}) + 1

y = W (\frac{- e ^{- x^{2}} + c _{1}}{5 e}) + 1

\frac{d y}{d x} = y (x^{2} + 1)

\frac{d y}{d x} = x y + 4 x

f^{^{'}} (x) = \frac{2 x}{( 2 x - 1 )} f (x)

\frac{d y}{d x} = y x^{2} - 1.2 y

y = y^{^{'}} \cdot (t^{2} - 14 t + 40)