(dy)/(dx)=(2x)/((y+1))

Lösung

\frac{d y}{d x} = \frac{2 x}{( y + 1 )}

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

Schritte zur Lösung

\frac{d y}{d x} = \frac{2 x}{( y + 1 )}

Solve separable ODE:

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

\frac{d y}{d x} = x y^{2} sin (x^{2})

\frac{d y}{d x} = 3 \frac{2}{9} y

y^{^{'}} + y cos (x) = 6 cos (x), y (0) = 8

x y^{^{'}} = (x - 1) y^{2}

y^{^{'}} = x y + y