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Beliebt Rechnen >

sum from n=2 to infinity of \sqrt[3]{n}

Lösung

n = 2 \sum \infty 3 n

Lösung

divergiert

Schritte zur Lösung

n = 2 \sum \infty 3 n

Seriendivergenztest anwenden:

divergiert

= divergiert

Beliebte Beispiele

sum from n=1 to infinity of 2/(n^n)

n = 1 \sum \infty \frac{2}{n ^{n}}

sum from n=2 to infinity of (5/6)^{3n}

n = 2 \sum \infty (\frac{5}{6})^{3 n}

sum from n=1 to infinity of (18^n)/(n!)

n = 1 \sum \infty \frac{1 8 ^{n}}{n !}

sum from k=1 to infinity of 1/(k^6)

k = 1 \sum \infty \frac{1}{k ^{6}}

sum from n=1 to infinity of 5/(1+n^2)

n = 1 \sum \infty \frac{5}{1 + n ^{2}}