sum from n=3 to infinity of (sin(npi))/n

Lösung

n = 3 \sum \infty \frac{sin ( nπ )}{n}

0

Schritte zur Lösung

n = 3 \sum \infty \frac{sin ( nπ )}{n}

\frac{sin ( nπ )}{n} = 0

= n = 3 \sum \infty 0

\sum 0 = 0

= 0

k = 0 \sum \infty e^{- k}

n = 0 \sum \infty \frac{3}{5 - n}

n = 0 \sum \infty \frac{1}{( n ( n + 1 ) )}

n = 0 \sum \infty 1 + (- 1)^{n}

n = 0 \sum \infty ln (5 - n)