(dy)/(dx)=x(x-1)

解答

\frac{d y}{d x} = x (x - 1)

y = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

求解步骤

\frac{d y}{d x} = x (x - 1)

替代

\frac{d y}{d x}

与

y^{'} (x)

y^{^{'}} (x) = x (x - 1)

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int x (x - 1) d x

\int x (x - 1) d x = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

y = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

\frac{d}{d x} (2 - \frac{1}{x})

\int (\frac{1}{ln ( x )} + ln (ln (x))) d x

d er i v a t i v e f (x) = lo g_{7} (x e^{x})

\int_{0}^{1} e^{5} d x

\frac{\partial}{\partial y} (z arcsin (\frac{y}{x}))