integral from-4 to 5 of-x+2

Lösung

\int_{- 4}^{5} - x + 2 d x

\frac{27}{2}

Dezimale

13.5

Schritte zur Lösung

\int_{- 4}^{5} - x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 4}^{5} x d x + \int_{- 4}^{5} 2 d x

\int_{- 4}^{5} x d x = \frac{9}{2}

\int_{- 4}^{5} 2 d x = 18

= - \frac{9}{2} + 18

Vereinfache

- \frac{9}{2} + 18 : \frac{27}{2}

= \frac{27}{2}

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