integral from-1 to 1 of-z^2+1

Lösung

\int_{- 1}^{1} - z^{2} + 1 d z

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} - z^{2} + 1 d z

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} z^{2} d z + \int_{- 1}^{1} 1 d z

\int_{- 1}^{1} z^{2} d z = \frac{2}{3}

\int_{- 1}^{1} 1 d z = 2

= - \frac{2}{3} + 2

Vereinfache

- \frac{2}{3} + 2 : \frac{4}{3}

= \frac{4}{3}

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