integral from 0 to 4 of (1+x/2)

Lösung

\int_{0}^{4} (1 + \frac{x}{2}) d x

8

Schritte zur Lösung

\int_{0}^{4} 1 + \frac{x}{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 1 d x + \int_{0}^{4} \frac{x}{2} d x

\int_{0}^{4} 1 d x = 4

\int_{0}^{4} \frac{x}{2} d x = 4

= 4 + 4

Vereinfache

= 8

\int_{1}^{4} \frac{u - 5}{u} d u

\int_{- 1}^{3} \frac{x ^{3} - 1}{x ^{3} + x} d x

\int_{0}^{2} 6 x^{5} e^{x^{3} y} d y

\int_{4}^{8} \frac{1}{x - 3} d x

\int_{- 1}^{3} 5 x x + 1 d x