integral from 9 to 100 of 1x^{-2}

Lösung

\int_{9}^{100} 1 x^{- 2} d x

\frac{91}{900}

Dezimale

0.10111 \dots

Schritte zur Lösung

\int_{9}^{100} 1 \cdot x^{- 2} d x

Vereinfache

1 \cdot x^{- 2} : \frac{1}{x ^{2}}

= \int_{9}^{100} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{9}^{100}

Berechne die Grenzen:

\frac{91}{900}

= \frac{91}{900}

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