integral from 3 to 5 of e^{2-x}

Lösung

\int_{3}^{5} e^{2 - x} d x

\frac{1}{e} - \frac{1}{e ^{3}}

Dezimale

0.31809 \dots

Schritte zur Lösung

\int_{3}^{5} e^{2 - x} d x

Wende U-Substitution an

= \int_{- 1}^{- 3} - e^{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 3}^{- 1} - e^{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{- 3}^{- 1} e^{u} d u)

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= - (- [e^{u}]_{- 3}^{- 1})

Vereinfache

= [e^{u}]_{- 3}^{- 1}

Berechne die Grenzen:

\frac{1}{e} - \frac{1}{e ^{3}}

= \frac{1}{e} - \frac{1}{e ^{3}}

\int_{- \infty}^{- 5} θ e^{θ} d θ

\int_{0}^{1.5} \frac{1}{8} x d x

\int_{0}^{1} 2 cos (x) d x

\int_{9}^{10} 1.5 x^{- 2.5} d x

\int_{2}^{4} - 6 x d x