integral from-2 to-1 of 4y^3+2/(y^3)

Lösung

\int_{- 2}^{- 1} 4 y^{3} + \frac{2}{y ^{3}} d y

- \frac{63}{4}

Dezimale

- 15.75

Schritte zur Lösung

\int_{- 2}^{- 1} 4 y^{3} + \frac{2}{y ^{3}} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} 4 y^{3} d y + \int_{- 2}^{- 1} \frac{2}{y ^{3}} d y

\int_{- 2}^{- 1} 4 y^{3} d y = - 15

\int_{- 2}^{- 1} \frac{2}{y ^{3}} d y = - \frac{3}{4}

= - 15 - \frac{3}{4}

Vereinfache

- 15 - \frac{3}{4} : - \frac{63}{4}

= - \frac{63}{4}

\int_{- 1}^{2} (\frac{3}{2})^{x^{2}} d x

\int_{2}^{3} 5 x^{4} - 8 x^{3} + 1 d x

\int_{0}^{1} - 2 x + 3 d x

\int_{0}^{1} 4 - y^{2} d y

\int_{1}^{3} 3 x^{2} d x