(\partial)/(\partial x)(sin(pi(2x-y)))

解

\frac{\partial}{\partial x} (sin (π (2 x - y)))

cos (π (2 x - y)) \cdot 2 π

解答ステップ

\frac{\partial}{\partial x} (sin (π (2 x - y)))

y

を定数として扱う

連鎖法則を適用:

cos (π (2 x - y)) \frac{\partial}{\partial x} (π (2 x - y))

= cos (π (2 x - y)) \frac{\partial}{\partial x} (π (2 x - y))

\frac{\partial}{\partial x} (π (2 x - y)) = 2 π

= cos (π (2 x - y)) \cdot 2 π