integral from 0 to 4 of 1/(sqrt(x-1))

Lösung

\int_{0}^{4} \frac{1}{x - 1} d x

- 2 i + 23

Schritte zur Lösung

\int_{0}^{4} \frac{1}{x - 1} d x

Bestimme unbestimmte (Singularitäts-)Punkte:

x = 1

Wenn

b, a < b < c, f (b) =

unbestimmt

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{1} \frac{1}{x - 1} d x + \int_{1}^{4} \frac{1}{x - 1} d x

\int_{0}^{1} \frac{1}{x - 1} d x = - 2 i

\int_{1}^{4} \frac{1}{x - 1} d x = 23

= - 2 i + 23

\int_{2}^{3} 25 d x

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