integral from 1 to 6 of sqrt(3x-2)

Lösung

\int_{1}^{6} 3 x - 2 d x

14

Schritte zur Lösung

\int_{1}^{6} 3 x - 2 d x

Wende U-Substitution an

= \int_{1}^{16} \frac{u}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{1}^{16} u d u

Wende die Potenzregel an

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{16}

Berechne die Grenzen:

42

= \frac{1}{3} \cdot 42

Vereinfache

= 14

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