integral from-1 to 2 of (x^2-2x)

Lösung

\int_{- 1}^{2} (x^{2} - 2 x) d x

0

Schritte zur Lösung

\int_{- 1}^{2} x^{2} - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} 2 x d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} 2 x d x = 3

= 3 - 3

Vereinfache

= 0

\int_{3}^{4} \frac{1}{x - 2 x} d x

\int_{0}^{4} \frac{x + 1}{x ^{2} + 2 x + 1} d x

\int_{0}^{0.5} e^{- x^{3}} d x

\int_{- 3}^{4} ∣ x + 1 ∣ d x

\int_{1}^{6} (x^{3} + x^{2} + 3) d x