integral of (6x-4)^2

Lösung

\int (6 x - 4)^{2} d x

12 x^{3} - 24 x^{2} + 16 x + C

Schritte zur Lösung

\int (6 x - 4)^{2} d x

Multipliziere aus

(6 x - 4)^{2} : 36 x^{2} - 48 x + 16

= \int 36 x^{2} - 48 x + 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 36 x^{2} d x - \int 48 x d x + \int 16 d x

\int 36 x^{2} d x = 12 x^{3}

\int 48 x d x = 24 x^{2}

\int 16 d x = 16 x

= 12 x^{3} - 24 x^{2} + 16 x

Füge eine Konstante zur Lösung hinzu

= 12 x^{3} - 24 x^{2} + 16 x + C

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