(d^3+d^2+4d+4)*y=0

Lösung

(d^{3} + d^{2} + 4 d + 4) \cdot y = 0

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

Schritte zur Lösung

(d^{3} + d^{2} + 4 d + 4) y = 0

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

y^{^{''}} - 2 y^{^{'}} - 3 y = 0, y (0) = 5, y^{^{'}} (0) = - 1

(d^{3} - 5 d^{2} + 8 d - 4) \cdot y = 0

(d^{3} - d^{2} - d + 1) y = 0

y^{^{'''}} - y^{^{'}} = 0, y (0) = 4, y^{^{'}} (0) = 0, y^{^{''}} (0) = 9

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = 2, y^{^{'}} (0) = 8