(d^3-3d+2)y=0

Lösung

(d^{3} - 3 d + 2) y = 0

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x}

Schritte zur Lösung

(d^{3} - 3 d + 2) y = 0

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x}

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x}

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = 3

(d^{3} + 1) y = 0

y^{^{'''}} + 2 y^{^{'}} - 3 y = 0, y (0) = e^{x}

y^{^{''}} + 4 y^{^{'}} = 2 y

(d^{4} - i^{2}) y = 0