d/(dh)(0.606h^3+0.27h^2+0.12*h)

解答

\frac{d}{d h} (0.606 \cdot h^{3} + 0.27 \cdot h^{2} + 0.12 \cdot h)

1.818 h^{2} + 0.54 h + 0.12

求解步骤

\frac{d}{d h} (0.606 h^{3} + 0.27 h^{2} + 0.12 h)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d h} (0.606 h^{3}) + \frac{d}{d h} (0.27 h^{2}) + \frac{d}{d h} (0.12 h)

\frac{d}{d h} (0.606 h^{3}) = 1.818 h^{2}

\frac{d}{d h} (0.27 h^{2}) = 0.54 h

\frac{d}{d h} (0.12 h) = 0.12

= 1.818 h^{2} + 0.54 h + 0.12

d er i v a t i v e (2 x^{2} - 4 x + 1) (6 x - 5)

d er i v a t i v e ln (2 x^{2})

d er i v a t i v e \frac{1}{( r + t )}

d er i v a t i v e \frac{1}{( 2 x )}

d er i v a t i v e \frac{( 4 - x )}{sin ^{2} ( x )}