derivative C(x)=-0.01x^2+7.2x-163

解

導関数

C (x) = - 0.01 x^{2} + 7.2 x - 163

- 0.02 x + 7.2

解答ステップ

\frac{d}{d x} (- 0.01 x^{2} + 7.2 x - 163)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.01 x^{2}) + \frac{d}{d x} (7.2 x) - \frac{d}{d x} (163)

\frac{d}{d x} (0.01 x^{2}) = 0.02 x

\frac{d}{d x} (7.2 x) = 7.2

\frac{d}{d x} (163) = 0

= - 0.02 x + 7.2 - 0

簡素化

= - 0.02 x + 7.2