limit as x approaches infinity of x*sin(7/x)

Lösung

x \to \infty lim (x \cdot sin (\frac{7}{x}))

7

Schritte zur Lösung

x \to \infty lim (x sin (\frac{7}{x}))

Umformung für L'Hopital

= x \to \infty lim (\frac{sin ( \frac{7}{x} )}{\frac{1}{x}})

Wende das L'Hopital Theorem an

= x \to \infty lim \frac{- \frac{7 c o s ( \frac{7}{x} )}{x ^{2}}}{- \frac{1}{x ^{2}}}

Vereinfache

\frac{- \frac{7 c o s ( \frac{7}{x} )}{x ^{2}}}{- \frac{1}{x ^{2}}} : 7 cos (\frac{7}{x})

= x \to \infty lim (7 cos (\frac{7}{x}))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 7 \cdot x \to \infty lim (cos (\frac{7}{x}))

Wende die Kettenregel für Grenzen an:

1

= 7 \cdot 1

Vereinfache

= 7

x \to 1 lim (\frac{x ^{2} - 3}{x - 9})

x \to - 1 + lim (1)

x \to 2 lim (4 x^{3} - 3 x - 5)

x \to 0 lim ((x + 2) \cdot e^{\frac{1}{x}})

x \to 0 lim (cos (x) sec (x))