integral from 1 to x^2 of 1/(t^5)

Lösung

\int_{1}^{x^{2}} \frac{1}{t ^{5}} d t

- \frac{1}{4 x ^{8}} + \frac{1}{4}

Schritte zur Lösung

\int_{1}^{x^{2}} \frac{1}{t ^{5}} d t

Wende die Potenzregel an

= [- \frac{1}{4 t ^{4}}]_{1}^{x^{2}}

Berechne die Grenzen:

- \frac{1}{4 x ^{8}} + \frac{1}{4}

= - \frac{1}{4 x ^{8}} + \frac{1}{4}

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