integral from x to 1 of y

Lösung

\int_{x}^{1} y d y

\frac{1 - x ^{2}}{2}

Schritte zur Lösung

\int_{x}^{1} y d y

Wende die Potenzregel an

= [\frac{y ^{2}}{2}]_{x}^{1}

Berechne die Grenzen:

\frac{1}{2} - \frac{x ^{2}}{2}

= \frac{1}{2} - \frac{x ^{2}}{2}

Vereinfache

= \frac{1 - x ^{2}}{2}

\int_{- 2}^{2} 1 + (2 x)^{2} d x

\int_{3}^{9} (\frac{1}{x ^{2}}) d x

\int_{- 2}^{4} (x + 2) d x

\int_{0}^{3} \frac{1}{27} (x + y) d y

\int_{4}^{16} x - 1 d x