integral from 0 to 1+sin(x) of t^2

Lösung

\int_{0}^{1 + s i n (x)} t^{2} d t

\frac{( sin ( x ) + 1 ) ^{3}}{3}

Schritte zur Lösung

\int_{0}^{1 + s i n (x)} t^{2} d t

Wende die Potenzregel an

= [\frac{t ^{3}}{3}]_{0}^{1 + s i n (x)}

Berechne die Grenzen:

\frac{( sin ( x ) + 1 ) ^{3}}{3}

= \frac{( sin ( x ) + 1 ) ^{3}}{3}

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