integral from 0 to pi/2 of 2cos(θ)

Lösung

\int_{0}^{\frac{π}{2}} 2 cos (θ) d θ

2

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} 2 cos (θ) d θ

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{\frac{π}{2}} cos (θ) d θ

Nutze das gemeinsame Integral :

\int cos (θ) d θ = sin (θ)

= 2 [sin (θ)]_{0}^{\frac{π}{2}}

Berechne die Grenzen:

1

= 2 \cdot 1

Vereinfache

= 2

\int_{0}^{4} x^{2} + 4 d x

\int_{- 8}^{0} 3 x d x

\int_{2}^{3} (8 x^{3} + 3 x^{2} + 6 x) d x

\int_{x^{4}}^{x^{6}} (2 t - 1)^{3} d t

\int_{- 1}^{2} 2 x^{2} - 2 x^{3} + 4 x d x