integral from 0 to 10 of-6x^2-12x+720

解答

\int_{0}^{10} - 6 x^{2} - 12 x + 720 d x

4600

求解步骤

\int_{0}^{10} - 6 x^{2} - 12 x + 720 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{10} 6 x^{2} d x - \int_{0}^{10} 12 x d x + \int_{0}^{10} 720 d x

\int_{0}^{10} 6 x^{2} d x = 2000

\int_{0}^{10} 12 x d x = 600

\int_{0}^{10} 720 d x = 7200

= - 2000 - 600 + 7200

化简

= 4600

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