integral from 0 to 2y of 1

Lösung

\int_{0}^{2 y} 1 d x

2 y

Schritte zur Lösung

\int_{0}^{2 y} 1 d x

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot x]_{0}^{2 y}

Vereinfache

= [x]_{0}^{2 y}

Berechne die Grenzen:

2 y

= 2 y

\int_{2}^{B} (2 x - 3)^{3} d x

\int_{3}^{6} \frac{6}{2 x - 3} d x

\int_{64}^{125} 3 y d y

\int_{4}^{7} 28 - 11 x + x^{2} d x

\int_{- 3}^{3} 1 9 - x^{2} d x