integral from 0 to pi/4 of 8sec(x)tan(x)

Lösung

\int_{0}^{\frac{π}{4}} 8 sec (x) tan (x) d x

8 (2 - 1)

Dezimale

3.31370 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{4}} 8 sec (x) tan (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{\frac{π}{4}} sec (x) tan (x) d x

Wende U-Substitution an

= 8 \cdot \int_{1}^{2} 1 d u

Integral einer Konstanten :

\int a d x = a x

= 8 [1 \cdot u]_{1}^{2}

Vereinfache

= 8 [u]_{1}^{2}

Berechne die Grenzen:

2 - 1

= 8 (2 - 1)

\int_{1}^{6} x^{2} - 2 x - 24 d x

\int_{1}^{2} 3 x d x

\int_{0}^{π} cos (s) sin (s) d s

\int_{- 2}^{3} (4 - x^{2}) d x

\int_{0}^{1} cos (\frac{π}{2} t) d t