integral from 0 to 3 of |t^2+4t-5|

Lösung

\int_{0}^{3} t^{2} + 4 t - 5 d t

\frac{52}{3}

Dezimale

17.33333 \dots

Schritte zur Lösung

\int_{0}^{3} t^{2} + 4 t - 5 d t

Entferne die Extremwerte

= \int_{0}^{1} - t^{2} - 4 t + 5 d t + \int_{1}^{3} t^{2} + 4 t - 5 d t

\int_{0}^{1} - t^{2} - 4 t + 5 d t = \frac{8}{3}

\int_{1}^{3} t^{2} + 4 t - 5 d t = \frac{44}{3}

= \frac{8}{3} + \frac{44}{3}

Vereinfache

\frac{8}{3} + \frac{44}{3} : \frac{52}{3}

= \frac{52}{3}

\int_{0}^{1} (x^{2} - x^{3})^{2} d x

\int_{- 2}^{0} x^{2} - 10 x d x

\int_{- π}^{π} t^{2} \cdot cos (n t) d t

\int_{- 1}^{2} e^{5 x - 4} d x

\int_{0}^{1} e^{- \frac{( x - 0.5 )}{2}} d x