integral from 1 to 4 of 8x^3-2x+e^x

Lösung

\int_{1}^{4} 8 x^{3} - 2 x + e^{x} d x

e^{4} - e + 495

Dezimale

546.87986 \dots

Schritte zur Lösung

\int_{1}^{4} 8 x^{3} - 2 x + e^{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 8 x^{3} d x - \int_{1}^{4} 2 x d x + \int_{1}^{4} e^{x} d x

\int_{1}^{4} 8 x^{3} d x = 510

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} e^{x} d x = e^{4} - e

= 510 - 15 + e^{4} - e

Vereinfache

= e^{4} - e + 495

\int_{- 5 π}^{4 π} cos^{2} (x) d x

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