integral from 1 to 4 of e^x-1/x

Lösung

\int_{1}^{4} e^{x} - \frac{1}{x} d x

e^{4} - e - 2 ln (2)

Dezimale

50.49357 \dots

Schritte zur Lösung

\int_{1}^{4} e^{x} - \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} e^{x} d x - \int_{1}^{4} \frac{1}{x} d x

\int_{1}^{4} e^{x} d x = e^{4} - e

\int_{1}^{4} \frac{1}{x} d x = 2 ln (2)

= e^{4} - e - 2 ln (2)

\int_{- 1}^{1} x^{3} - 2 x^{2} - x + 2 d x

\int_{- 2}^{1} (3 + 2 x) d x

\int_{0}^{2} \frac{3 x ^{2}}{8} d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 18) d x

\int_{0}^{4} y e^{y} d y