integral from-2 to x of 1-x^4

Lösung

\int_{- 2}^{x} 1 - x^{4} d x

x + 2 - \frac{x ^{5} + 32}{5}

Schritte zur Lösung

\int_{- 2}^{x} 1 - x^{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{x} 1 d x - \int_{- 2}^{x} x^{4} d x

\int_{- 2}^{x} 1 d x = x + 2

\int_{- 2}^{x} x^{4} d x = \frac{x ^{5} + 32}{5}

= x + 2 - \frac{x ^{5} + 32}{5}

\int_{2}^{3} \frac{x}{ln ( x - 1 )} d x

\int_{- 2}^{3} \frac{2}{x ^{3}} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} u cos (u) d u

\int_{- 2}^{1} (2 x + 2) d x

\int_{0}^{π} (9 e^{x} + 6 sin (x)) d x