integral from 1 to 2 of (6xy^2-(4x)/y)

Lösung

\int_{1}^{2} (6 x y^{2} - \frac{4 x}{y}) d y

- 4 x ln (2) + 14 x

Schritte zur Lösung

\int_{1}^{2} 6 x y^{2} - \frac{4 x}{y} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} \frac{4 x}{y} d y + \int_{1}^{2} 6 x y^{2} d y

\int_{1}^{2} \frac{4 x}{y} d y = 4 x ln (2)

\int_{1}^{2} 6 x y^{2} d y = 14 x

= - 4 x ln (2) + 14 x

\int_{1}^{2} (\frac{x + 1}{x})^{2} d x

\int_{- 3}^{2} (- 2 x) d x

\int_{0}^{1} 15 x e^{x} d x

\int_{0}^{1} x \cdot 2 (1 - x) d x

\int_{- 2}^{2} x^{2} + x + 2 d x