integral from 1 to 3 of x(x-1)

Lösung

\int_{1}^{3} x (x - 1) d x

\frac{14}{3}

Dezimale

4.66666 \dots

Schritte zur Lösung

\int_{1}^{3} x (x - 1) d x

Multipliziere aus

x (x - 1) : x^{2} - x

= \int_{1}^{3} x^{2} - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} x d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} x d x = 4

= \frac{26}{3} - 4

Vereinfache

\frac{26}{3} - 4 : \frac{14}{3}

= \frac{14}{3}

\int_{0}^{a r c s i n (x)} (cos (t)) d t

\int_{- \frac{π}{2}}^{\frac{π}{2}} I n (cos (x)) d x

\int_{1}^{9} 10 u d u

\int_{- 1}^{1} x sin (x^{2}) d x

\int_{0}^{10} \frac{x}{16 + 2 x} d x