integral from 0 to 2 of (x-2)^4

Lösung

\int_{0}^{2} (x - 2)^{4} d x

\frac{32}{5}

Dezimale

6.4

Schritte zur Lösung

\int_{0}^{2} (x - 2)^{4} d x

Wende U-Substitution an

= \int_{- 2}^{0} u^{4} d u

Wende die Potenzregel an

= [\frac{u ^{5}}{5}]_{- 2}^{0}

Berechne die Grenzen:

\frac{32}{5}

= \frac{32}{5}

\int_{0}^{b} x^{3} d x

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