integral from b to infinity of 1/(1+x^2)

Lösung

\int_{b}^{\infty} \frac{1}{1 + x ^{2}} d x

\frac{π}{2} - arctan (b)

Schritte zur Lösung

\int_{b}^{\infty} \frac{1}{1 + x ^{2}} d x

Berechne das unbestimmte Integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x) + C

Berechne die Grenzen:

\int_{b}^{\infty} \frac{1}{1 + x ^{2}} d x = \frac{π}{2} - arctan (b)

= \frac{π}{2} - arctan (b)

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