integral from 0 to 2pi of-4sin(x)

Lösung

\int_{0}^{2 π} - 4 sin (x) d x

0

Schritte zur Lösung

\int_{0}^{2 π} - 4 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int_{0}^{2 π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - 4 [- cos (x)]_{0}^{2 π}

Berechne die Grenzen:

0

= - 4 \cdot 0

Vereinfache

= 0

\int_{1}^{2} (2 x - x^{2}) d x

\int_{1}^{4} (5 - e) d x

\int_{0}^{3} (x^{3} - 4 x^{2} + 3 x) d x

\int_{0}^{t} e^{τ} d τ

\int_{0}^{1} \frac{6}{5} (x^{2} + y) d x