integral from 1 to 5 of (x^2+x)

Lösung

\int_{1}^{5} (x^{2} + x) d x

\frac{160}{3}

Dezimale

53.33333 \dots

Schritte zur Lösung

\int_{1}^{5} x^{2} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x + \int_{1}^{5} x d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} x d x = 12

= \frac{124}{3} + 12

Vereinfache

\frac{124}{3} + 12 : \frac{160}{3}

= \frac{160}{3}

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