integral from-1 to 1 of (6x^2+2x+5)

Lösung

\int_{- 1}^{1} (6 x^{2} + 2 x + 5) d x

14

Schritte zur Lösung

\int_{- 1}^{1} 6 x^{2} + 2 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 6 x^{2} d x + \int_{- 1}^{1} 2 x d x + \int_{- 1}^{1} 5 d x

\int_{- 1}^{1} 6 x^{2} d x = 4

\int_{- 1}^{1} 2 x d x = 0

\int_{- 1}^{1} 5 d x = 10

= 4 + 0 + 10

Vereinfache

= 14

\int_{0}^{1} \frac{2 x ^{2}}{x ^{2} + 1} d x

\int_{x}^{2 x} \frac{1}{1 + t ^{4}} d t

\int_{2}^{4} 8 d x

\int_{2}^{4} (x^{3}) d x

\int_{0}^{3} x 4 - x d x