integral from 2pi to-4pi of sin(x)

Lösung

\int_{2 π}^{- 4 π} sin (x) d x

0

Schritte zur Lösung

\int_{2 π}^{- 4 π} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 4 π}^{2 π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{- 4 π}^{2 π}

Berechne die Grenzen:

0

= - 0

Vereinfache

= 0

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\int_{4}^{5} x (x^{2} - 16)^{3} d x