integral from 0 to 1 of y^3-y^2

Lösung

\int_{0}^{1} y^{3} - y^{2} d y

- \frac{1}{12}

Dezimale

- 0.08333 \dots

Schritte zur Lösung

\int_{0}^{1} y^{3} - y^{2} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y^{3} d y - \int_{0}^{1} y^{2} d y

\int_{0}^{1} y^{3} d y = \frac{1}{4}

\int_{0}^{1} y^{2} d y = \frac{1}{3}

= \frac{1}{4} - \frac{1}{3}

Vereinfache

\frac{1}{4} - \frac{1}{3} : - \frac{1}{12}

= - \frac{1}{12}

\int_{- 1}^{3} x^{- 3} d x

\int_{0}^{3} e^{- \frac{1}{2} x} d x

\int_{0}^{- \infty} e^{3 x} d x

\int_{0}^{\frac{π}{4}} (cos (x)) d x

\int_{1}^{3} 9 - x^{2} d x