integral from 0 to 40 of 0.3x

Lösung

\int_{0}^{40} 0.3 x d x

240

Schritte zur Lösung

\int_{0}^{40} 0.3 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.3 \cdot \int_{0}^{40} x d x

Wende die Potenzregel an

= 0.3 [\frac{x ^{2}}{2}]_{0}^{40}

Vereinfache

= 0.3 [0.5 x^{2}]_{0}^{40}

Berechne die Grenzen:

800

= 0.3 \cdot 800

Vereinfache

= 240

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