integral from 0 to 1 of 4x^3+2x

Lösung

\int_{0}^{1} 4 x^{3} + 2 x d x

2

Schritte zur Lösung

\int_{0}^{1} 4 x^{3} + 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x^{3} d x + \int_{0}^{1} 2 x d x

\int_{0}^{1} 4 x^{3} d x = 1

\int_{0}^{1} 2 x d x = 1

= 1 + 1

Vereinfache

= 2

\int_{0}^{1} 2 x sin (nπ x) d x

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