integral from 2 to 4 of 3x-1+2x^2

Lösung

\int_{2}^{4} 3 x - 1 + 2 x^{2} d x

\frac{160}{3}

Dezimale

53.33333 \dots

Schritte zur Lösung

\int_{2}^{4} 3 x - 1 + 2 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 3 x d x - \int_{2}^{4} 1 d x + \int_{2}^{4} 2 x^{2} d x

\int_{2}^{4} 3 x d x = 18

\int_{2}^{4} 1 d x = 2

\int_{2}^{4} 2 x^{2} d x = \frac{112}{3}

= 18 - 2 + \frac{112}{3}

Vereinfache

18 - 2 + \frac{112}{3} : \frac{160}{3}

= \frac{160}{3}

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