integral from-pi/4 to 0 of sec(x)tan(x)

Lösung

\int_{- \frac{π}{4}}^{0} sec (x) tan (x) d x

- 2 + 1

Dezimale

- 0.41421 \dots

Schritte zur Lösung

\int_{- \frac{π}{4}}^{0} sec (x) tan (x) d x

Wende U-Substitution an

= \int_{2}^{1} 1 d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} 1 d u

Integral einer Konstanten :

\int a d x = a x

= - [1 \cdot u]_{1}^{2}

Vereinfache

= - [u]_{1}^{2}

Berechne die Grenzen:

2 - 1

= - (2 - 1)

Vereinfache

= - 2 + 1

\int_{1}^{5} 7 - 2 x d x

\int_{1}^{4} (1 + \frac{1}{x} + \frac{1}{x ^{2}}) d x

\int_{0}^{1} 3 x + 5 d x

\int_{0}^{t} (t - w) e^{5 w} d w

\int_{0}^{4} e^{x} x^{2} d x