integral from 1/2 to 1 of (x^{-3}-16)

Lösung

\int_{\frac{1}{2}}^{1} (x^{- 3} - 16) d x

- \frac{13}{2}

Dezimale

- 6.5

Schritte zur Lösung

\int_{\frac{1}{2}}^{1} x^{- 3} - 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{\frac{1}{2}}^{1} x^{- 3} d x - \int_{\frac{1}{2}}^{1} 16 d x

\int_{\frac{1}{2}}^{1} x^{- 3} d x = \frac{3}{2}

\int_{\frac{1}{2}}^{1} 16 d x = 8

= \frac{3}{2} - 8

Vereinfache

\frac{3}{2} - 8 : - \frac{13}{2}

= - \frac{13}{2}

\int_{x}^{2} sin (t^{4}) d t

\int_{0}^{3} 8 - 2 x^{2} d x

\int_{0}^{π} tan (x) cos^{2} (x) d x

\int_{0}^{2} x^{2} - 4 x d x

\int_{0}^{π} \frac{1}{sin ( x )} d x