integral from 0 to 1/2 of 1/(1+x^2)

Lösung

\int_{0}^{\frac{1}{2}} \frac{1}{1 + x ^{2}} d x

arctan (\frac{1}{2})

Dezimale

0.46364 \dots

Schritte zur Lösung

\int_{0}^{\frac{1}{2}} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{\frac{1}{2}}

Berechne die Grenzen:

arctan (\frac{1}{2})

= arctan (\frac{1}{2})

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