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人気のある微分積分 >

integral from-1 to 1 of 3x^4e^{(1-x^5)}

解

\int_{- 1}^{1} 3 x^{4} e^{(1 - x^{5})} d x

解

\frac{3 ( e ^{2} - 1 )}{5}

+1

十進法表記

3.83343 \dots

解答ステップ

\int_{- 1}^{1} 3 x^{4} e^{1 - x^{5}} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{1} x^{4} e^{1 - x^{5}} d x

u置換積分法を適用する

= 3 \cdot \int_{2}^{0} - \frac{e ^{u}}{5} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 3 (- \int_{0}^{2} - \frac{e ^{u}}{5} d u)

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- (- \frac{1}{5} \cdot \int_{0}^{2} e^{u} d u))

共通積分を使用する:

\int e^{u} d u = e^{u}

= 3 (- (- \frac{1}{5} [e^{u}]_{0}^{2}))

簡素化

3 (- (- \frac{1}{5} [e^{u}]_{0}^{2})) : \frac{3}{5} [e^{u}]_{0}^{2}

= \frac{3}{5} [e^{u}]_{0}^{2}

限度を計算する:

e^{2} - 1

= \frac{3}{5} (e^{2} - 1)

簡素化

= \frac{3 ( e ^{2} - 1 )}{5}

グラフ

人気の例

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